std::rotate
From cppreference.com
Defined in header <algorithm>
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(1) | ||
template< class ForwardIt > void rotate( ForwardIt first, ForwardIt n_first, ForwardIt last ); |
(until C++11) | |
template< class ForwardIt > ForwardIt rotate( ForwardIt first, ForwardIt n_first, ForwardIt last ); |
(since C++11) (until C++20) |
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template< class ForwardIt > constexpr ForwardIt rotate( ForwardIt first, ForwardIt n_first, ForwardIt last ); |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt > ForwardIt rotate( ExecutionPolicy&& policy, |
(2) | (since C++17) |
1) Performs a left rotation on a range of elements.
Specifically,
std::rotate
swaps the elements in the range [first, last)
in such a way that the element n_first
becomes the first element of the new range and n_first - 1
becomes the last element. A precondition of this function is that
[first, n_first)
and [n_first, last)
are valid ranges.2) Same as (1), but executed according to
policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueParameters
first | - | the beginning of the original range |
n_first | - | the element that should appear at the beginning of the rotated range |
last | - | the end of the original range |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-ForwardIt must meet the requirements of ValueSwappable and ForwardIterator.
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-The type of dereferenced ForwardIt must meet the requirements of MoveAssignable and MoveConstructible.
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Return value
(none) |
(until C++11) |
The iterator equal to |
(since C++11) |
Complexity
Linear in the distance between first
and last
Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the three standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
template <class ForwardIt> ForwardIt rotate(ForwardIt first, ForwardIt n_first, ForwardIt last) { if(first == n_first) return last; if(n_first == last) return first; ForwardIt next = n_first; do { std::iter_swap(first++, next++); if (first == n_first) n_first = next; } while (next != last); ForwardIt ret = first; for(next = n_first; next != last; ) { std::iter_swap(first++, next++); if(first == n_first) n_first = next; else if(next == last) next = n_first; } return ret; } |
Example
std::rotate
is a common building block in many algorithms. This example demonstrates insertion sort:
Run this code
#include <vector> #include <iostream> #include <algorithm> int main() { std::vector<int> v{2, 4, 2, 0, 5, 10, 7, 3, 7, 1}; std::cout << "before sort: "; for (int n: v) std::cout << n << ' '; std::cout << '\n'; // insertion sort for (auto i = v.begin(); i != v.end(); ++i) { std::rotate(std::upper_bound(v.begin(), i, *i), i, i+1); } std::cout << "after sort: "; for (int n: v) std::cout << n << ' '; std::cout << '\n'; // simple rotation to the left std::rotate(v.begin(), v.begin() + 1, v.end()); std::cout << "simple rotate left : "; for (int n: v) std::cout << n << ' '; std::cout << '\n'; // simple rotation to the right std::rotate(v.rbegin(), v.rbegin() + 1, v.rend()); std::cout << "simple rotate right: "; for (int n: v) std::cout << n << ' '; std::cout << '\n'; }
Output:
before sort: 2 4 2 0 5 10 7 3 7 1 after sort: 0 1 2 2 3 4 5 7 7 10 simple rotate left: 1 2 2 3 4 5 7 7 10 0 simple rotate right: 0 1 2 2 3 4 5 7 7 10
See also
copies and rotate a range of elements (function template) |