std::make_from_tuple

Defined in header `<tuple>`
template <class T, class Tuple> constexpr T make_from_tuple(Tuple&& t);		(since C++17)

Construct an object of type T, using the elements of the tuple t as the arguments to the constructor.

Parameters

t - tuple whose elements to be used as arguments to the constructor of T

Return value

The constructed T object.

Notes

The tuple need not be std::tuple, and instead may be anything that supports std::get and std::tuple_size; in particular, std::array and std::pair may be used.

Due to guaranteed copy elision, T need not be movable.

Possible implementation

namespace detail {
template <class T, class Tuple, std::size_t... I>
constexpr T make_from_tuple_impl( Tuple&& t, std::index_sequence<I...> )
{
  return T(std::get<I>(std::forward<Tuple>(t))...);
}
} // namespace detail

template <class T, class Tuple>
constexpr T make_from_tuple( Tuple&& t )
{
    return detail::make_from_tuple_impl<T>(std::forward<Tuple>(t),
        std::make_index_sequence<std::tuple_size_v<std::remove_reference_t<Tuple>>>{});
}

Example

Run this code

#include <iostream>
#include <tuple>

struct Foo {
    Foo(int first, float second, int third) {
        std::cout << first << ", " << second << ", " << third << "\n";
    }
};

int main()
{
   auto tuple = std::make_tuple(42, 3.14f, 0);
   std::make_from_tuple<Foo>(std::move(tuple));
}

Output:

42, 3.14, 0

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