std::forward
Defined in header <utility>
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template< class T > T&& forward( typename std::remove_reference<T>::type& t ) noexcept; |
(1) | (since C++11) (until C++14) |
template< class T > constexpr T&& forward( typename std::remove_reference<T>::type& t ) noexcept; |
(1) | (since C++14) |
template< class T > T&& forward( typename std::remove_reference<T>::type&& t ) noexcept; |
(2) | (since C++11) (until C++14) |
template< class T > constexpr T&& forward( typename std::remove_reference<T>::type&& t ) noexcept; |
(2) | (since C++14) |
When t
is a forwarding reference (a function argument that is an rvalue reference to a cv-unqualified function template parameter), this overload forwards the argument to another function with the value category it had when passed to the calling function.
For example, if used in wrapper such as the following, the template behaves as described below:
template<class T> void wrapper(T&& arg) { // arg is always lvalue foo(std::forward<T>(arg)); // Forward as lvalue or as rvalue, depending on T }
- If a call to
wrapper()
passes an rvaluestd::string
, thenT
is deduced tostd::string
(notstd::string&
,const std::string&
, orstd::string&&
), andstd::forward
ensures that an rvalue reference is passed tofoo
. - If a call to
wrapper()
passes a const lvaluestd::string
, thenT
is deduced toconst std::string&
, andstd::forward
ensures that a const lvalue reference is passed tofoo
. - If a call to
wrapper()
passes a non-const lvaluestd::string
, thenT
is deduced tostd::string&
, andstd::forward
ensures that a non-const lvalue reference is passed tofoo
.
This overload makes it possible to forward a result of an expression (such as function call), which may be rvalue or lvalue, as the original value category of a forwarding reference argument.
For example, if a wrapper does not just forward its argument, but calls a member function on the argument, and forwards its result:
// transforming wrapper template<class T> void wrapper(T&& arg) { foo(forward<decltype(forward<T>(arg).get())>(forward<T>(arg).get())); }
where the type of arg may be
struct Arg { int i = 1; int get() && { return i; } // call to this overload is rvalue int& get() & { return i; } // call to this overload is lvalue };
Attempting to forward an rvalue as an lvalue, such as by instantiating the form (2) with lvalue reference type T, is a compile-time error.
Notes
See template argument deduction for the special rules behind forwarding references (T&&
used as a function parameter) and forwarding references for other detail.
Parameters
t | - | the object to be forwarded |
Return value
static_cast<T&&>(t)
Example
This example demonstrates perfect forwarding of the parameter(s) to the argument of the constructor of class T
. Also, perfect forwarding of parameter packs is demonstrated.
#include <iostream> #include <memory> #include <utility> #include <array> struct A { A(int&& n) { std::cout << "rvalue overload, n=" << n << "\n"; } A(int& n) { std::cout << "lvalue overload, n=" << n << "\n"; } }; class B { public: template<class T1, class T2, class T3> B(T1&& t1, T2&& t2, T3&& t3) : a1_{std::forward<T1>(t1)}, a2_{std::forward<T2>(t2)}, a3_{std::forward<T3>(t3)} { } private: A a1_, a2_, a3_; }; template<class T, class U> std::unique_ptr<T> make_unique1(U&& u) { return std::unique_ptr<T>(new T(std::forward<U>(u))); } template<class T, class... U> std::unique_ptr<T> make_unique(U&&... u) { return std::unique_ptr<T>(new T(std::forward<U>(u)...)); } int main() { auto p1 = make_unique1<A>(2); // rvalue int i = 1; auto p2 = make_unique1<A>(i); // lvalue std::cout << "B\n"; auto t = make_unique<B>(2, i, 3); }
Output:
rvalue overload, n=2 lvalue overload, n=1 B rvalue overload, n=2 lvalue overload, n=1 rvalue overload, n=3
Complexity
Constant
See also
(C++11) |
obtains an rvalue reference (function template) |
(C++11) |
obtains an rvalue reference if the move constructor does not throw (function template) |