std::wmemmove
From cppreference.com
Defined in header <cwchar>
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wchar_t* wmemmove( wchar_t* dest, const wchar_t* src, std::size_t count ); |
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Copies exactly count
successive wide characters from the wide character array pointed to by src
to the wide character array pointed to by dest
.
If count
is zero, the function does nothing.
The arrays may overlap: copying takes place as if the wide characters were copied to a temporary wide character array and then copied from the temporary array to dest
.
Parameters
dest | - | pointer to the wide character array to copy to |
src | - | pointer to the wide character array to copy from |
count | - | number of wide characters to copy |
Return value
Returns a copy of dest
Notes
This function is not locale-sensitive and pays no attention to the values of the wchar_t objects it copies: nulls as well as invalid characters are copied too.
Example
Run this code
#include <iostream> #include <cwchar> #include <locale> #include <clocale> int main() { std::setlocale(LC_ALL, "en_US.utf8"); std::wcout.imbue(std::locale("en_US.utf8")); wchar_t str[] = L""; std::wcout << str << '\n'; std::wmemmove(str+4, str+3, 3); // copy from [] to [] std::wcout << str << '\n'; }
Possible output:
See also
copies a certain amount of wide characters between two non-overlapping arrays (function) | |
moves one buffer to another (function) | |
(C++11) |
copies a range of elements to a new location (function template) |
copies a range of elements in backwards order (function template) |